3x^2+22xy+19y^2=0

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Solution for 3x^2+22xy+19y^2=0 equation: 


Simplifying
3x2 + 22xy + 19y2 = 0

Reorder the terms:
22xy + 3x2 + 19y2 = 0

Solving
22xy + 3x2 + 19y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + y)(3x + 19y) = 0


Subproblem 1
Set the factor '(x + y)' equal to zero and attempt to solve:

Simplifying
x + y = 0

Solving
x + y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1y' to each side of the equation.
x + y + -1y = 0 + -1y

Combine like terms: y + -1y = 0
x + 0 = 0 + -1y
x = 0 + -1y
Remove the zero:
x = -1y

Simplifying
x = -1y

Subproblem 2
Set the factor '(3x + 19y)' equal to zero and attempt to solve:

Simplifying
3x + 19y = 0

Solving
3x + 19y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-19y' to each side of the equation.
3x + 19y + -19y = 0 + -19y

Combine like terms: 19y + -19y = 0
3x + 0 = 0 + -19y
3x = 0 + -19y
Remove the zero:
3x = -19y

Divide each side by '3'.
x = -6.333333333y

Simplifying
x = -6.333333333y
Solution
x = {-1y, -6.333333333y}

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